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Which is the equation of the plane through (1, 2, 3) with normal vector (2, -1, 4)?
A2x - y + 4z = 10
B2x - y + 4z = 12
C2x - y + 4z = 16
D2x + y + 4z = 12
Answer & Solution
Correct answer: B. 2x - y + 4z = 12
Using normal form, the constant is 2(1) - 2 + 4(3) = 12, giving 2x - y + 4z = 12.
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