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How far is the plane 6x + 3y + 2z = 14 from the origin?

A1 unit
B14 units
C7 units
D2 units
Answer & Solution
Correct answer: D. 2 units
The normal vector has length 7 since 36 + 9 + 4 = 49, so the distance is 14/7 = 2.
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