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For axes rotated counterclockwise by θ, the old x equals
Ax'cosθ - y'sinθ
Bx'sinθ + y'cosθ
Cx'sinθ - y'cosθ
Dx'cosθ + y'sinθ
Answer & Solution
Correct answer: A. x'cosθ - y'sinθ
Resolving the point onto the old x axis gives x = x'cosθ - y'sinθ.
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