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Expand (x + 1/x)^2 first, then integrate it term by term to get
Ax^3/3 + 2x - 1/x + C
Bx^3/3 + 2x + 1/x + C
C(x + 1/x)^3/3 + C
Dx^3/3 + 2 ln x + C
Answer & Solution
Correct answer: A. x^3/3 + 2x - 1/x + C
Expanding gives x^2 + 2 + x^(-2), and integrating term by term gives x^3/3 + 2x - 1/x.
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