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Writing x/(x + 1) as 1 - 1/(x + 1), its integral is
Ax^2/2 ln|x + 1| + C
Bx + ln|x + 1| + C
Cln|x + 1| + C
Dx - ln|x + 1| + C
Answer & Solution
Correct answer: D. x - ln|x + 1| + C
Writing x/(x + 1) as 1 - 1/(x + 1) and integrating gives x - ln|x + 1|.
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