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Applying by parts with u = x and dv = e^x dx, the integral of x e^x dx is
Ax e^x + C
B(x - 1) e^x + C
Cx^2 e^x/2 + C
D(x + 1) e^x + C
Answer & Solution
Correct answer: B. (x - 1) e^x + C
With u = x and dv = e^x dx, the result is x e^x minus the integral of e^x, which is (x - 1) e^x.
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