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Put t = ln x in the integral of (ln x)^3/x dx. Result is

A(ln x)^4/4 + C
B(ln x)^4 + C
C(ln x)^3 ln x + C
D3(ln x)^2 + C
Answer & Solution
Correct answer: A. (ln x)^4/4 + C
Putting t = ln x gives dt = dx/x, so the integral becomes t^4/4.
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