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With t = x^2, the integral of 2x e^(x^2) dx becomes
Ax^2 e^(x^2) + C
B2e^(x^2) + C
Ce^(x^2) + C
De^(2x) + C
Answer & Solution
Correct answer: C. e^(x^2) + C
Putting t = x^2 gives dt = 2x dx, so the integral reduces to the integral of e^t.
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