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A lead slab (G = 5.6e9 Pa) is sheared by stress 1.8e6 Pa over L = 0.5 m. The top edge moves how far?
A0.016 mm
B1.6 mm
C0.16 mm
D16 mm
Answer & Solution
Correct answer: C. 0.16 mm
Displacement = stress x L / G = 1.8e6 x 0.5 / 5.6e9, which is 1.6e-4 m or 0.16 mm.
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