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A solenoid of 500 turns and length 0.5 m carries 4 A. What is the central field?
A2.5 x 10^-3 T
B5.0 x 10^-3 T
C1.0 x 10^-2 T
D5.0 x 10^-4 T
Answer & Solution
Correct answer: B. 5.0 x 10^-3 T
n = 500 / 0.5 = 1000 per metre, so B = mu0 n I = 4 pi x 10^-7 x 1000 x 4 = 5.0 x 10^-3 T.
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