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A proton (m = 1.67 x 10^-27 kg) circles in a 1 T field. What is its frequency?
A1.5 x 10^7 Hz
B1.5 x 10^6 Hz
C9.6 x 10^7 Hz
D2.4 x 10^7 Hz
Answer & Solution
Correct answer: A. 1.5 x 10^7 Hz
f = qB / 2 pi m = 1.6 x 10^-19 / (2 pi x 1.67 x 10^-27) which is about 1.5 x 10^7 Hz.
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