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A 1.2 m string fixed at both ends vibrates in its fundamental mode. What is the wavelength?
A0.6 m
B4.8 m
C1.2 m
D2.4 m
Answer & Solution
Correct answer: D. 2.4 m
With lambda = 2L for n = 1, the wavelength is 2 x 1.2 = 2.4 m.
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