The equation z⁸ = 1 has how many complex roots?
A8
B6
C4
D16
Answer & Solution
Correct answer: A. 8
A polynomial of degree 8 has eight roots, and here all eight are distinct.
Keep practising De Moivre's Formula
Browse all De Moivre's Formula questions for TS EAPCET (Engineering), or explore more Mathematics topics.
Related questions
If ω is a non-real cube root of unity, (1 + ω)³ equalsFor a cube root of unity ω, the value of 1 + ω² + ω⁴ isIf a complex number z has modulus 2, the modulus of z⁵ isDe Moivre's formula can be derived from the exponential law together with which result?By Euler's formula, e^(iπ) equalsAdjacent sixth roots of unity differ in argument byThe principal fourth root of -1 has argumentThe three cube roots of 8 in the complex plane are