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By Euler's form e^(iθ) = cos θ + i sin θ, the power (e^(iθ))ⁿ equals
Ae^(iθ + n)
Be^(θ + in)
Ce^(inθ)
Dn e^(iθ)
Answer & Solution
Correct answer: C. e^(inθ)
Raising an exponential to the power n multiplies its exponent by n, giving e^(inθ).
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