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For an ellipse with semi-axes a > b and focal distance c, which relation holds?
Ac² = a² - b²
Bc = a² - b²
Cc² = a² + b²
Dc² = b² - a²
Answer & Solution
Correct answer: A. c² = a² - b²
The end of the minor axis is at distance a from each focus, so a² = b² + c² and hence c² = a² - b².
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