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For x greater than 1, d/dx of arcosh x is what?
A1/√(x² - 1)
B1/(1 - x²)
C1/(x√(x² - 1))
D1/√(x² + 1)
Answer & Solution
Correct answer: A. 1/√(x² - 1)
If y = arcosh x then x = cosh y, so dy/dx = 1/sinh y = 1/√(x² - 1) for x > 1.
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