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Radical axis of x²+y²+6x-4y-3=0 and x²+y²-2x+8y+5=0 is
A2x - 3y - 2 = 0
B2x - 3y + 2 = 0
C2x + 3y - 2 = 0
D3x - 2y - 2 = 0
Answer & Solution
Correct answer: A. 2x - 3y - 2 = 0
Subtraction gives 8x - 12y - 8 = 0, and dividing by 4 yields 2x - 3y - 2 = 0.
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