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Home › TS EAMCET › Mathematics › Coordinate Geometry: System of Circles › The chord of contact from (5,0) to x²+y²=9 is

The chord of contact from (5,0) to x²+y²=9 is

Ax = 5
B9x = 5
C5x = 9
D5x = 3
Answer & Solution
Correct answer: C. 5x = 9
The chord of contact from (x1, y1) is x·x1 + y·y1 = r², so 5x = 9.
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