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Circles through the common points of circle S=0 and line L=0 form the family
AS · L = 0
BS + λL = 0
CS + L² = 0
DλS - L² = 0
Answer & Solution
Correct answer: B. S + λL = 0
The expression S + λL vanishes wherever both S and L vanish, so it covers every circle through those points.
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