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The radical centre of x²+y²=1, x²+y²-4x+3=0 and x²+y²-4y+3=0 is
A(2, 2)
B(1, 1)
C(1, 0)
D(0, 1)
Answer & Solution
Correct answer: B. (1, 1)
The pairwise radical axes are x = 1 and y = 1, which meet at (1, 1).
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