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The vertex of the parabola y^2 - 4y - 8x + 12 = 0 is

A(1, -2)
B(2, 1)
C(-1, 2)
D(1, 2)
Answer & Solution
Correct answer: D. (1, 2)
Completing the square gives (y-2)^2 = 8(x-1), a parabola with vertex (1, 2).
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