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The ellipse 9x^2+25y^2+18x-100y-116=0 has eccentricity
A16/25
B5/4
C4/5
D3/5
Answer & Solution
Correct answer: C. 4/5
With a = 5, b = 3 we get c = 4, so e = c/a = 4/5.
Related questions
The foci of the ellipse 9x^2+25y^2+18x-100y-116=0 areIf axes shift h to the right and k up, a fixed point appears movedIf axes are rotated counterclockwise, a fixed point appears rotatedA second-degree equation in x, y, z that is not a cylinder, plane, line or point gives aIn three dimensions the origin moves to (h, k, l). Old z equalsWhen axes are translated, the slope of a given lineWhich expression keeps its value when axes are rotated about the origin?The axes are rotated through any angle. The circle x^2 + y^2 = 9 becomes