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Shifting the origin to (2, -3) turns x^2 + y^2 - 4x + 6y - 3 = 0 into
Ax'^2 + y'^2 = 3
Bx'^2 + y'^2 = 10
Cx'^2 + y'^2 = 13
Dx'^2 + y'^2 = 16
Answer & Solution
Correct answer: D. x'^2 + y'^2 = 16
Completing squares gives (x-2)^2 + (y+3)^2 = 3 + 4 + 9 = 16.
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