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The midpoint of the segment from the origin to a point of x^2 + y^2 = 16 lies on
Ax^2 + y^2 = 8
Bx^2 + y^2 = 4
Cx^2 + y^2 = 2
Dx^2 + y^2 = 16
Answer & Solution
Correct answer: B. x^2 + y^2 = 4
The midpoint is (x/2, y/2) of a point on the circle, so its coordinates satisfy x^2 + y^2 = 4.
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