Home › TS EAPCET (Engineering) › Mathematics › Locus (mathematics) › Distances of P from (3, 0) and (-3, 0) add to 10…
Distances of P from (3, 0) and (-3, 0) add to 10. Locus of P is
Ax^2/25 + y^2/16 = 1
Bx^2/25 + y^2/9 = 1
Cx^2/5 + y^2/4 = 1
Dx^2/16 + y^2/25 = 1
Answer & Solution
Correct answer: A. x^2/25 + y^2/16 = 1
Here 2a = 10 so a = 5, c = 3 and b^2 = 25 - 9 = 16, giving x^2/25 + y^2/16 = 1.
Related questions
The foci of the ellipse 9x^2+25y^2+18x-100y-116=0 areIf axes shift h to the right and k up, a fixed point appears movedIf axes are rotated counterclockwise, a fixed point appears rotatedA second-degree equation in x, y, z that is not a cylinder, plane, line or point gives aIn three dimensions the origin moves to (h, k, l). Old z equalsWhen axes are translated, the slope of a given lineWhich expression keeps its value when axes are rotated about the origin?The axes are rotated through any angle. The circle x^2 + y^2 = 9 becomes