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P is as far from (0, 2) as from the line y = -2. Its locus is
Ax^2 = 2y
Bx^2 = 4y
Cy^2 = 8x
Dx^2 = 8y
Answer & Solution
Correct answer: D. x^2 = 8y
x^2 + (y-2)^2 = (y+2)^2 simplifies to x^2 = 8y, a parabola with focus (0, 2).
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