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Home › TS EAPCET (Engineering) › Mathematics › Differentiation › For x = t^2 and y = t^3 with t not 0, dy/dx equals

For x = t^2 and y = t^3 with t not 0, dy/dx equals

A3t^2
B2t/3
C3t/2
Dt^2
Answer & Solution
Correct answer: C. 3t/2
dy/dt = 3t^2 and dx/dt = 2t, so dy/dx = 3t^2 / 2t = 3t/2.
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