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For 2x^3 - 5x^2 + x + 6 = 0, which cannot be a rational root?
A3/2
B2/3
C6
D-1/2
Answer & Solution
Correct answer: B. 2/3
A rational root p/q needs p dividing 6 and q dividing 2, and the denominator 3 in 2/3 does not divide 2.
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