Home › AP EAPCET (Engineering) › Mathematics › Algebra: Theory of Equations › x^4 - 1 = 0 has how many non-real complex roots?
x^4 - 1 = 0 has how many non-real complex roots?
A1
B0
C2
D4
Answer & Solution
Correct answer: C. 2
The roots are 1, -1, i and -i, so exactly two of them, i and -i, are non-real.
Related questions
How many real roots does x^3 - 1 = 0 have?In Descartes's rule, a root of multiplicity k is counted asFor x^3 + x^2 - x - 1, replacing x by -x gives how many sign changes?A polynomial has exactly one sign change. How many positive roots does it have?x^3 + 2x^2 + 3x + 4 = 0 has at most how many positive roots?How many sign changes does x^3 - 3x^2 + x - 5 have in its coefficients?Who is credited with first grasping the general root-coefficient principle, beyond positivVieta originally derived his root-coefficient relations for roots that were