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ΔG° for glucose phosphorylation is +13.8 kJ/mol at 298 K. Kc is about:
A3.81 × 10^3
B1.38 × 10^1
C3.81 × 10^-3
D1.38 × 10^-1
Answer & Solution
Correct answer: C. 3.81 × 10^-3
ln Kc = -13800/(8.314 × 298) = -5.57, so Kc = e^-5.57 = 3.81 × 10^-3.
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