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What is the value of Kw for water at 298 K?
A14.0 exactly
B1.0 × 10^-7
C1.0 × 10^14
D1.0 × 10^-14
Answer & Solution
Correct answer: D. 1.0 × 10^-14
Kw = [H3O+][OH-], and each ion is 10^-7 M in pure water at 25 °C, giving 10^-14.
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