Home › TS EAPCET (Engineering) › Mathematics › Straight Lines › A line passes through (−1, 2) and (3, −2). Its e…
A line passes through (−1, 2) and (3, −2). Its equation is
Ax − y + 3 = 0
Bx + y + 1 = 0
Cx + y − 1 = 0
Dx − y − 1 = 0
Answer & Solution
Correct answer: C. x + y − 1 = 0
Slope is (−2 − 2)/(3 + 1) = −1, so y − 2 = −(x + 1), which is x + y − 1 = 0.
Related questions
The lines 3x + 2y − 5 = 0 and kx + 4y + 1 = 0 are parallel. Find k.The points (1, 2), (3, 6) and (k, 10) are collinear. Find k.A line is perpendicular to 2x − 3y + 4 = 0. What is its slope?Find the distance between the parallel lines y = 2x + 3 and y = 2x − 2.What is the perpendicular distance of the point (2, 1) from the line 3x − 4y + 5 = 0?In the general linear equation Ax + By + C = 0, what must hold for A and B?The line 3x + 4y = 12 and the two coordinate axes enclose a triangle of areaWhich line cuts off intercepts 4 on the x-axis and 5 on the y-axis?