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A toroid has 1200 turns, minor radius 2.0 cm and major radius 15 cm. What is its self-inductance?

A2.414 mH
B24.14 mH
C0.2414 mH
D241.4 mH
Answer & Solution
Correct answer: A. 2.414 mH
L = mu0 N^2 r^2 / (2R) works out to about 2.414 x 10^-3 H.
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