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A closely wound coil of 200 turns has L = 10 mH and carries 4 mA. What is the flux through each turn?
A2 x 10^-7 Wb
B4 x 10^-5 Wb
C8 x 10^-3 Wb
D2 x 10^-5 Wb
Answer & Solution
Correct answer: A. 2 x 10^-7 Wb
Total linkage is L i = 4 x 10^-5 Wb, and dividing by 200 turns gives 2 x 10^-7 Wb per turn.
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