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A magnet of moment 3 A m^2 is at 30 degrees to a 0.4 T field. What torque acts on it?

A1.2 N m
B0.6 N m
C0.3 N m
D1.04 N m
Answer & Solution
Correct answer: B. 0.6 N m
Torque = mB sin30 = 3 x 0.4 x 0.5 = 0.6 N m.
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