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A 20 V potential is applied across a 1.25 mm spark-plug gap. The field in the gap is

A2.5 x 10^-2 V/m
B1.6 x 10^4 V/m
C1.6 x 10^2 V/m
D2.5 x 10^4 V/m
Answer & Solution
Correct answer: B. 1.6 x 10^4 V/m
E = V/d = 20 / (1.25 x 10^-3) = 1.6 x 10^4 V/m.
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