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A 0.2 kg stone is whirled in a circle of radius 0.5 m at 5 m/s. The string tension is:
A5 N
B2.5 N
C10 N
D20 N
Answer & Solution
Correct answer: C. 10 N
F = m v squared / r = 0.2 x 25 / 0.5 = 10 N.
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