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A 100 V rms source drives a series circuit with R = 3 Ω and impedance 5 Ω. What power is dissipated?

A2000 W
B600 W
C1500 W
D1200 W
Answer & Solution
Correct answer: D. 1200 W
Irms = 100/5 = 20 A and cos φ = 3/5, so P = 100 × 20 × 0.6 = 1200 W.
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