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What is the unit vector along the vector 2i - 2j + k?
A(2i - 2j + k)/3
B(2i - 2j + k)/9
C(2i - 2j + k)/2
D(2i - 2j + k)/5
Answer & Solution
Correct answer: A. (2i - 2j + k)/3
The magnitude is sqrt(4 + 4 + 1) = 3, so dividing the vector by 3 gives the unit vector.
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