alleryStart learning →What does the integral of 2^x over [0, 1] equal in terms of log 2?
Alog 2
B1/log 2
C2 log 2
D1
Answer & Solution
Correct answer: B. 1/log 2
The primitive is 2^x/log 2, so the value is (2 - 1)/log 2 = 1/log 2.
Keep practising Definite Integration
Browse all Definite Integration questions for MHT-CET, or explore more Mathematics topics.
Related questions
Evaluate the integral of dx/root x between x = 4 and x = 9.A chain-rule integral: cos 3x integrated over [0, pi/6] givesFind the definite integral of 1/(1 + x) from x = 0 up to x = 1.Even-function shortcut: the integral of x^4 over [-2, 2] equalsWith upper bound log 2, the integral of e^x starting from 0 isCompute the integral of 3x^2 + 2x as x moves from 1 to 2.Show that the integral of x^3 cos x over [-1, 1] equals which number?Evaluate the integral of sin^4 x/(sin^4 x + cos^4 x) from x = 0 to x = pi/2.