What is the value of the log-tan integral of log(1 + tan x) over [0, pi/4]?
A(pi/4) log 2
Bpi log 2
C(pi/2) log 2
D(pi/8) log 2
Answer & Solution
Correct answer: D. (pi/8) log 2
Using x -> pi/4 - x gives log(1 + tan x) + log(2/(1 + tan x)) = log 2, so 2I = (pi/4) log 2 and I = (pi/8) log 2.
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