alleryStart learning →Let I be the integral of log(tan x) on [0, pi/2]. Using the mirrored integrand log(cot x), I equals
Alog 2
B-pi/2
C0
Dpi/2
Answer & Solution
Correct answer: C. 0
Replacing x by pi/2 - x turns log tan x into log cot x = -log tan x, so I = -I and I = 0.
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