alleryStart learning →Take A = {1, 2, 3, 4, 5, 6, 7}. The claim 'some x in A has x – 4 = 3' is
AIt is false (F)
BIt is open
CIt is not fixed
DIt is true (T)
Answer & Solution
Correct answer: D. It is true (T)
x = 7 gives 7 – 4 = 3, so a witness exists.
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