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Applying the chain rule to the reciprocal of g(x), what is d/dx of 1/g(x)?
Ag'(x)/g(x)^2
B-1/g(x)^2
C-g'(x)/g(x)^2
D1/g'(x)
Answer & Solution
Correct answer: C. -g'(x)/g(x)^2
The reciprocal function has derivative -1/u^2, and the chain rule multiplies by g'(x).
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