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What is the tangent at (x₁, y₁) to x² + y² + 2gx + 2fy + c = 0?
Axx₁ + yy₁ + g(x − x₁) + f(y − y₁) + c = 0
Bxx₁ + yy₁ + 2g(x + x₁) + 2f(y + y₁) + c = 0
Cxx₁ + yy₁ + g(x + x₁) + f(y + y₁) + c = 0
Dxx₁ + yy₁ + g(x + x₁) + f(y + y₁) = c
Answer & Solution
Correct answer: C. xx₁ + yy₁ + g(x + x₁) + f(y + y₁) + c = 0
Replacing x² by xx₁, 2x by (x + x₁), y² by yy₁ and 2y by (y + y₁) gives the tangent equation.
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