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Which is a parametric form of the circle (x − 3)² + (y + 2)² = 16?
Ax = 3 + 4 cos θ, y = −2 + 4 sin θ
Bx = −3 + 4 cos θ, y = 2 + 4 sin θ
Cx = 3 + 16 cos θ, y = −2 + 16 sin θ
Dx = 4 + 3 cos θ, y = 4 − 2 sin θ
Answer & Solution
Correct answer: A. x = 3 + 4 cos θ, y = −2 + 4 sin θ
The centre is (3, −2) and the radius is 4, so x − 3 = 4 cos θ and y + 2 = 4 sin θ.
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