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What is the equation of the circle with centre (3, 4) that passes through the origin?
Ax² + y² + 6x + 8y = 0
Bx² + y² − 6x − 8y + 25 = 0
Cx² + y² − 6x − 8y = 0
Dx² + y² − 3x − 4y = 0
Answer & Solution
Correct answer: C. x² + y² − 6x − 8y = 0
The radius equals the distance from (3, 4) to the origin, 5, so (x − 3)² + (y − 4)² = 25 simplifies to x² + y² − 6x − 8y = 0.
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