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The equation x² + y² + 2gx + 2fy + c = 0 represents a real circle when which condition holds?

Ag² + f² + c > 0
Bg + f − c > 0
Cg² + f² − c > 0
Dg² − f² − c > 0
Answer & Solution
Correct answer: C. g² + f² − c > 0
The radius is √(g² + f² − c), which is real and positive only when g² + f² − c > 0.
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