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A weak monobasic acid is 0.05% dissociated in its 0.02 M solution. Its Ka is

A5 x 10^-9
B2.5 x 10^-7
C5 x 10^-4
D1 x 10^-6
Answer & Solution
Correct answer: A. 5 x 10^-9
Alpha = 5 x 10^-4, so Ka = alpha squared x c = 25 x 10^-8 x 2 x 10^-2 = 5 x 10^-9.
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