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A 1800 kg lift rises at 2 m/s against 4000 N friction. Motor power? (g = 10)
A40 kW
B22 kW
C36 kW
D44 kW
Answer & Solution
Correct answer: D. 44 kW
Force = 1800 x 10 + 4000 = 22000 N, so P = 22000 x 2 = 44000 W.
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